How do you find the antiderivative of #sinx#?

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Answer 1 · 2018-04-10T12:19:26

#intsinxdx=-cosx+"c"#

The antiderivative of sinx is its integral. The integral of #sinx# is a standard results and evaluates to

#intsinxdx=-cosx+"c"#

Answer 2 · 2018-04-10T12:53:05

#-cos(x)+C#

The anti-derivative of a function #f(x)# is the same thing as the integral of the function, i.e. it's #intf(x) \ dx#.

So, the anti-derivative of #sin(x)# will be:

#intsin(x) \ dx#

This is a common integral, and it equals,

#=-cos(x)+C#