# How do you find the area between #y=1/2x^3+2, y=x+1, x=0, x=2#?

##### 1 Answer

Nov 9, 2016

graph{(1/2x^3+2-y)(x+1-y)(x-2)x=0 [-6.67, 9.14, -0.72, 7.18]}

#### Explanation:

First of all

To explain this call

Then

and

So f has a local minimum in

Then the area is given by