Question

How do you find the area between `y=x^2` and `y=8x`?

Answer 1

Area`=8^3/6`

Explanation:

Firstly we have to find the intersection between them.
Let' solve the system of equation `y=x^2` and `y=8x`
we have `x^2=8x` so that there are two solution `x=0` and `x=8`

the sought are is `int_0^8(8x-x^2)dx=8x^2/2-x^3/3|_0^8=8^3/2-8^3/3=8^3/6`