Question

How do you find the area bounded by the x axis, y axis, `y=x^2+1` and `x=2`?

Answer 1

`14/3`

Explanation:

graph{y=x^2+1 [-8.75, 11.25, -1.52, 8.48]}
limit of x is from `x=0` to `x=2`
Function is `y=x^2+1`

Area Between the curve and X-axis is
`Area=int_0^2ydx=int_0^2(x^2+1)dx`

`Area=[x^3/3+x]_0^2=[2^3/3+2-0-0]=8/3+2=14/3`