# How do you find the area of a rectangle with base 5 yd and height 3 ft?

$\triangle = 22.5$ sq.ft
We know that,area of $\triangle A B C = \frac{1}{2} \cdot A B \cdot B C , w h e n \angle B = \frac{\pi}{2}$
We have, base $B C = 5$ yards=(5*3) feet=15feet and height $A B = 3$ feet.
So,$\triangle = \frac{1}{2} \left(3\right) \left(15\right) = 22.5$ sq.ft