# How do you find the area of a triangleGHI, if angleI = 15^@, g = 14.2 , and h = 7.9?

Nov 6, 2014

The height $k$ of Triangle GHI with HI as its base can be found by

$\text{(Height)} = 7.9 \sin \left({15}^{\circ}\right)$

The area $A$ of Triangle GHI can be found by

$A = \frac{1}{2} \text{(Base)(Height)} = \frac{1}{2} \cdot 14.2 \cdot 7.9 \sin \left({15}^{\circ}\right) \approx 14.52$

I hope that this was helpful.