# How do you find the area of an equilateral triangle with sides measuring 6 meters?

$\frac{\sqrt{3}}{4} \cdot {6}^{2} = 15.59$ ${m}^{2}$
$A = \frac{\sqrt{3}}{4} \cdot {a}^{2}$, (where $a =$ side of the triangle)
Given that $a = 6 m$,
$\implies A = \frac{\sqrt{3}}{4} \cdot {6}^{2} = 15.59 {m}^{2}$