# How do you find the area of region bounded by the graphs of y +x= 6 and y +2x-3=0?

##### 1 Answer

You need at least one more line to bound the area.

See below for possibilities

#### Explanation:

The two given equations form the graph below:

graph{(y+2x-3)(y+x-6)=0 [-13.19, 12.13, -1.93, 10.73]}

These intersecting lines divide the plane into four (infinite) regions.

**Possible intended third boundary [1]: the X-axis**

In this case we have a triangle with a base of

**Possible intended third boundary [2]: the Y-axis**

In this case we hav a triangle with a base of

**Possible intended third and fourth boundaries [3]: both the X and Y-axes**

This would give us a quadrilateral region with an area equal to the difference between the two triangular areas calculated above.