Question

How do you find the area under one period of y=sinx?

Answer 1

See explanation.

Explanation:

The period of `sinx` is `2pi`, so integrate `sinx dx` from `a` to `a+2pi`

`int_a^(a+2pi) sinx dx = {: -cosx]_a^(a+2pi)`

`= = -cos(a+2pi) + cosa = 0`