# How do you find the asymptote(s) or holes of # f(x) = (x-1) / (x^2-1)#?

##### 1 Answer

May 18, 2016

#### Answer:

We have a vertical asymptote at

#### Explanation:

Although

As we have

As the degree of numerator is less than that of denominator, we do not have any horizontal or slanting asymptote.

graph{(x-1)/(x^2-1) [-10, 10, -5, 5]}