# How do you find the asymptotes for #f(x) =(x^2 - 16)/(x^2- 5x + 4)#?

##### 1 Answer

Feb 14, 2016

#### Answer:

Vertical asymptotes are

#### Explanation:

The vertical asymptotes are given by restrictions on the domain and hence come from the zeroes of the denominator.

Putting

i.e.

Hence

and vertical asymptotes are

Since, numerator and denominator of the function are of same degree, horizontal asymptote is found by dividing the leading terms

i.e.

Hence horizontal asymptote is