# How do you find the asymptotes for #h(x) = (x+6 )/(x^2 - 36)#?

##### 1 Answer

Feb 28, 2016

#### Answer:

Vertical asymptote at

Horizontal asymptote at

#### Explanation:

By factorizing the denominator as a difference of 2 squares, we get that

Hence a vertical asymptote occurs at points leading to division by zero in the denominator, ie when

Note that

Horizontal asymptotes occur at

The plotted graph verifies the existence of these asymptotes.

graph{(x+6)/(x^2-36) [-3.71, 16.29, -5.6, 4.4]}