# How do you find the asymptotes for #y= (2x^3-5x+3) / (x^2-5x+4)#?

##### 1 Answer

Mar 12, 2016

#### Answer:

Vertical asymptote at

#### Explanation:

In

Hence, as denominator will be zero for

Further as degree of numerator in

graph{(2x^3-5x+3)/(x^2-5x+4) [-15, 15, -5, 5]}