How do you find the axis of symmetry, and the maximum or minimum value of the function $y = (x – 5)^2 + 10$ ?

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Answer 1 · 2016-02-10T11:15:06

$x=5$ is the axis of symmetry

Solve for the vertex :
From the equation: $y=(x-5)^2+10$ , vertex is at $(h, k)=(5, 10)$

Axis of symmetry is $x=5$ a vertical line passing through the vertex

graph{(y-(x-5)^2-10)(y-1000000x+5(1000000))=0 [-40,40,-5, 45]}

How do you find the axis of symmetry, and the maximum or minimum value of the function y = (x – 5)^2 + 10y = (x – 5)^2 + 10?