How do you find the axis of symmetry, and the maximum or minimum value of the function #y=x^2-4x+7#?

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Answer 1 · 2016-06-25T04:34:28

the axis of simmetry is #x=2# and the minimum value is in x=2

Since the equation of the axis is

#x=-b/2a#

when

#y=ax^2+bx+c#

and, in this case, a=1 and b=-4,

the axis of simmetry is

#x=4/2=2#

Then, since

#y'=2x-4#

and y'=0 when x=2

the minimum value is in x=2