# How do you find the axis of symmetry, graph and find the maximum or minimum value of the function y = 3x^2 - 12x - 2?

Minimum value $f \left(2\right) = - 14$ at the lowest point $\left(2 , - 14\right)$
$x = 2$ the axis of symmetry

#### Explanation:

$y = 3 {x}^{2} - 12 x - 2$
by completing the square method
$y = 3 \left({x}^{2} - 4 x\right) - 2$
$y = 3 \left({x}^{2} - 4 x + 4 - 4\right) - 2$
$y = 3 {\left(x - 2\right)}^{2} - 12 - 2$
$y = 3 {\left(x - 2\right)}^{2} - 14$
$\frac{1}{3} \left(y + 14\right) = {\left(x - 2\right)}^{2}$

$\frac{1}{3} \left(y - - 14\right) = {\left(x - 2\right)}^{2}$

graph{y=3x^2-12x-2[-5,35,-15,5]}

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