How do you find the axis of symmetry, graph and find the maximum or minimum value of the function $y= 1/20 x^2$ ?

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Answer 1 · 2018-01-02T01:23:36

Axis of symmetry: $x=0$ i.e the $y-$ axis
$y_min = 0$

$y=1/20x^2$

The graph of $y$ is a parabola, of the form: $ax^2+bx+c$
Where: $a=1/20, b=c=0$

The axis of symmetry of $y$ will occur where: $x=-b/(2a)$

$:.$ Axis of symmetry is where: $x=0$ i.e the $y-$ axis

Since, $a>0 -> y$ will have a minimum value

The minimum value of $y =y_min$ will lie on the axis of symmetry.

Hence, $y_min= 1/20*0^2 = 0$

We can see these results from the graph of $y$ below:

graph{1/20x^2 [-10, 10, -5, 5]}

How do you find the axis of symmetry, graph and find the maximum or minimum value of the function y= 1/20 x^2y= 1/20 x^2?