# How do you find the axis of symmetry, graph and find the maximum or minimum value of the function y = 3x^2 + 6x + 5?

Dec 17, 2017

Axis of symmetry: $x = - 1$
Maximum or minimum?: minimum
For graph, refer to explanation.

#### Explanation:

$y = 3 {x}^{2} + 6 x + 5$

Axis of symmetry means the line that makes the graph symmetrical.

This equation is written in standard form, or $a {x}^{2} + b x + c$, meaning that to find the axis of symmetry, we must find $- \frac{b}{2 a}$.

We know that $a = 3$, $b = 6$, and $c = 5$.

$- \frac{b}{2 a} = - \frac{6}{2 \left(3\right)} = - \frac{6}{6} = - 1$

We write the axis of symmetry as a line, so $x = - 1$.

The maximum/minimum of a quadratic equation is also the vertex, since it is the highest or lowest point of the parabola.

To find the vertex, we need to do a couple things:

We have already found the axis of symmetry, which was $x = - 1$. Since that is the vertical line where the graph will be symmetrical, that means it's the x-coordinate of the vertex.

Now, we need to find the y-coordinate of the vertex, and to do so, we plug back our value of x back into the equation and solve:
$y = 3 {\left(- 1\right)}^{2} + 6 \left(- 1\right) + 5$
$y = 3 \left(1\right) - 6 + 5$
$y = 3 - 6 + 5$
$y = 2$

So our vertex is $\left(- 1 , 2\right)$.

To find whether it is a maximum or minimum, we look at the coefficient. The coefficient here is $3$.

When the coefficient is positive (like in this case), then the vertex is the minimum.

When the coefficient is negative, then the vertex is the maximum.

Here is the graph of our equation $y = 3 {x}^{2} + 6 x + 5$: