How do you find the axis of symmetry, graph and find the maximum or minimum value of the function y-4 = – 2(x – 1)^2?

1 Answer
Jan 27, 2016

The axis of symmetry is x=1.
The vertex is (1,4).

Explanation:

y-4=-2(x-1)^2

Put the equation into vertex form, y=a(x-h)^2+k, by adding 4 to both sides of the equation.

y=-2(x-1)^2+4, where a=-2, h=1, k=4

The axis of symmetry is the vertical line that divides a parabola into two equal halves. For an equation in vertex form, the axis of symmetry is x=h.

The axis of symmetry is x=1.

The vertex is the minimum or maximum point of a parabola. In this case, because a=-2, the parabola opens downward and the vertex is the maximum point.

The vertex in vertex form is (h,k).
The vertex is (1,4).

graph{y=-2(x-1)^2+4 [-10, 10, -5, 5]}