Question

How do you find the axis of symmetry of the graph of `f(x)=-2x^2-x-2`?

Answer 1

`"axis of symmetry" ->x_s = -1/4`

Explanation:

Let the axis of symmetry be `x_s`

Write as: `" "-2(x^2+1/2x)-2`

Now consider the `color(red)(+1/2)` from `color(red)(+1/2x)`

`"axis of symmetry"=x_s =(-1/2)xx(color(red)(+1/2)) = -1/4`