How do you find the center and radius of the circle given (x-sqrt5)^2+y^2-8y=9?

1 Answer
Dec 6, 2017

Centre : (sqrt5 ,4) and radius: 5 unit

Explanation:

The center-radius form of the circle equation is

(x – h)^2 + (y – k)^2 = r^2 with at the point (h, k)

and the radius being r.

(x-sqrt5)^2 +y^2-8y =9 or

(x-sqrt5)^2 +y^2-8y+16 =9+16 or

(x-sqrt5)^2 +(y-4)^2 =5^2

:. h= sqrt5 , k= 4 and r=5

Therefore centre is at (sqrt5 ,4) and radius is 5 unit [Ans]