# How do you find the center and radius of the circle #x^2 + y^2 – 8x – 6y – 75 = 0#?

##### 1 Answer

Jul 4, 2016

Centre:

Radius:

#### Explanation:

Complete the square for

#0 = x^2+y^2-8x-6y-75#

#= (x^2-8x+16)+(y^2-6y+9)-100#

#= (x-4)^2+(y-3)^2-10^2#

Add

#(x-4)^2+(y-3)^2=10^2#

This is in the standard form of the equation of a circle:

#(x-h)^2+(y-k)^2=r^2#

where