# How do you find the center and radius of the circle (x-5) ^2 + (y+3) ^2 = 16?

Centre $\left(5 , - 3\right)$, Radius $= 4.$
We know that the equation (eqn.) of a circle having centre at point (pt.) $\left(h , k\right)$ & radius $r$ is given by ${\left(x - h\right)}^{2} + {\left(y - k\right)}^{2} = {r}^{2.}$
Comparing this with the given eqn., we get centre at the pt. $\left(5 , - 3\right)$ and radius $r = 4.$