# How do you find the center and radius of  (x – 9)^2 + y^2 = 484?

Feb 19, 2016

$\left(9 , 0\right)$ is the center and $22$ is radius.

#### Explanation:

Equation of a circle with center at ()a, b) and radius $r$ can be expressed as

${\left(x - a\right)}^{2} + {\left(y - b\right)}^{2} = {r}^{2}$, as any point $\left(x , y\right)$ will be at a distance of $r$ from center at $\left(a , b\right)$.

As the equation (x–9)^2+y^2=484 can be written as

(x–9)^2+(y-o)^2=22^2

It is obvious from the equation that

$\left(9 , 0\right)$ is the center and $22$ is radius.