How do you find the center and radius of # (x – 9)^2 + y^2 = 484#?

1 Answer
Feb 19, 2016

Answer:

#(9, 0)# is the center and #22# is radius.

Explanation:

Equation of a circle with center at #()a, b)# and radius #r# can be expressed as

#(x-a)^2+(y-b)^2=r^2#, as any point #(x,y)# will be at a distance of #r# from center at #(a,b)#.

As the equation #(x–9)^2+y^2=484# can be written as

#(x–9)^2+(y-o)^2=22^2#

It is obvious from the equation that

#(9, 0)# is the center and #22# is radius.