How do you find the center of (x+2)^2+(y-3)^2=50?

Nov 24, 2016

circle of centre $\left(- 2 , 3\right)$ and radius $\sqrt{50}$

Explanation:

A circle of centre $\left(a , b\right)$ and radius $r$ has equation:

${\left(x - a\right)}^{2} + {\left(y - b\right)}^{2} = {r}^{2}$

Comparing with;

${\left(x + 2\right)}^{2} + {\left(y - 3\right)}^{2} = 50$

We can see that this represents a circle of centre $\left(- 2 , 3\right)$ and radius $\sqrt{50} \left(\approx 7\right)$

graph{(x+2)^2 + (y-3)^2=50 [-21.83, 18.17, -6.24, 13.76]}