How do you find the center, vertices, foci and asymptotes of #x^2-y^2=100#?

1 Answer
Jan 15, 2016

It can be recognized as the equation for a circle as it follows the general form #(x-h)^2 +(y-k)^2 = r^2#

Explanation:

This equation #x^2 +y^2 = 100# can be rewritten as
#(x-0)^2 +(y - 0)^2 =10^2#

It can be recognized as the equation for a circle as it follows the general form #(x-h)^2 +(y-k)^2 = r^2# where #(h,k)# is the center and #r# is the radius.

Therefore it does not have vertices, foci or asymptotes.

The center is #(0,0)# and the radius is #10#