# How do you find the coefficient of #x^2# in the expansion of #(x+2)^5#?

##### 1 Answer

#### Answer:

The coefficient of the

#### Explanation:

First, we need to find the sixth row of Pascal's Triangle to determine the coefficient of the non-simplified terms of the expansion of the binomial expression. Remember that Pascal's Triangle begins with

```
1
/ \
1 1
/ \ / \
1 2 1
/ \ / \ / \
1 3 3 1
/ \ / \ / \ / \
1 4 6 4 1
/ \ / \ / \ / \ / \
1 5 10 10 5 1
```

Remember that in this case,

Combining that with the coefficients from Pascal's Truangle gives us this expansion of

#1(x^5)(2^0) + 5(x^4)(2^1) + 10(x^3)(2^2) + 10(x^2)(2^3) + 5(x^1)(2^4) + 1(x^0)(2^5)

The fourth term is the

#10(x^2)(2^3) = 10(x^2)(8) = 80x^2

So, the coefficient of the