# How do you find the coordinates of the center, foci, the length of the major and minor axis given #(x+11)^2/144+(y-5)^2/121=1#?

##### 1 Answer

Centre is

#### Explanation:

As the equation

As such here centre is

For focus we should calculate eccentricity of ellipse and as

and foci are given by

graph{(x+11)^2/144+(y-5)^2/121=1 [-30, 10, -8, 18]}

**Note** - Here we had