# How do you find the coordinates of the terminal points corresponding to the following arc length on the unit circle: -25π/6?

Jul 20, 2015

Find coordinates of terminal arc $x = \frac{- 25 \pi}{6}$
$x = \frac{\sqrt{3}}{2}$
$y = - \frac{1}{2}$

#### Explanation:

$\frac{- 25 \pi}{6} \to \left(- \frac{\pi}{6} - 24 \frac{\pi}{6}\right) \to \left(- \frac{\pi}{6} - 4 \pi\right) \to \left(- \frac{\pi}{6}\right)$

The terminal M of the arc $x = \frac{- 25 \pi}{6}$ has as coordinates:

$x = \cos \left(- \frac{\pi}{6}\right) = \cos \left(\frac{\pi}{6}\right) = \frac{\sqrt{3}}{2}$

$y = \sin \left(- \frac{\pi}{6}\right) = - \sin \left(\frac{\pi}{6}\right) = - \frac{1}{2}$