# How do you find the coordinates of the vertices, foci, and the equation of the asymptotes for the hyperbola #(x+6)^2/36-(y+3)^2/9=1#?

##### 1 Answer

#### Answer:

**Vertices are at** **Focii are at**

**and
asymptotes are**

#### Explanation:

This is standard form of the equation of a hyperbola with center

The vertices are

Vertices are at

Focii are at

Each hyperbola has two asymptotes that intersect at the center of

the hyperbola. The asymptotes pass through the vertices of a

rectangle of dimensions

center at

Equation of asymptotes are

Therefore, asymptotes are

graph{(x+6)^2/36-(y+3)^2/9=1 [-80, 80, -40, 40]}