How do you find the critical points to graph #y= 2 sin (-2x+pi) +1#?

1 Answer
Jun 24, 2018

Answer:

As below

Explanation:

Standard form of sine function is #y = A sin (Bx - C) + D#

Given #y = 2 sin(-2x + pi) + 1#

#A = 2, B = -2, C = -pi, D = 1#

#Amplitude = |A| = 2#

#"Period " = (2pi) / |B| = (2pi) / 2 = pi#

#"Phase Shift " = -C / B = -pi / -2 = pi/2, " " pi/2 " to the RIGHT"#

#"Vertical Shift " = D = 1#