How do you find the critical points to graph y= 2 sin (-2x+pi) +1?

Jun 24, 2018

As below

Explanation:

Standard form of sine function is $y = A \sin \left(B x - C\right) + D$

Given $y = 2 \sin \left(- 2 x + \pi\right) + 1$

$A = 2 , B = - 2 , C = - \pi , D = 1$

$A m p l i t u \mathrm{de} = | A | = 2$

$\text{Period } = \frac{2 \pi}{|} B | = \frac{2 \pi}{2} = \pi$

$\text{Phase Shift " = -C / B = -pi / -2 = pi/2, " " pi/2 " to the RIGHT}$

$\text{Vertical Shift } = D = 1$