# How do you find the derivative of 8^(2x)?

$\frac{d}{\mathrm{dx}} {8}^{2 x} = {8}^{2 x} \cdot 2 \ln 8$
Applying the rule $\frac{d}{\mathrm{dx}} {a}^{u \left(x\right)} = {a}^{u} \cdot \ln a \cdot \frac{\mathrm{du}}{\mathrm{dx}}$, to this question we get
$\frac{d}{\mathrm{dx}} {8}^{2 x} = {8}^{2 x} \cdot \ln 8 \cdot 2$