Question

How do you find the derivative of `e^(1+lnx)`?

Answer 1

`d/dx(e^(1+lnx))=e`

Explanation:

We need `d/dx(e^(1+lnx))`

First, rewrite the expression using `a^(b+c)-=a^b*a^c`

`e^(1+lnx)=e^1*e^lnx=xe`

`d/dx(xe)=e`

`therefored/dx(e^(1+lnx))=e`