# How do you find the derivative of e^(-2t)?

Differential of ${e}^{- 2 t}$ is $- \frac{2}{e} ^ \left(2 t\right)$
As differential of ${e}^{t}$ is ${e}^{t}$
Differential of ${e}^{- 2 t}$ using chain rule
is ${e}^{- 2 t} \times - 2 = - \frac{2}{e} ^ \left(2 t\right)$