Question

How do you find the derivative of `F(x) = 1/(x-5)`?

Answer 1

`(dF)/(dx)=(-1)/(x-5)^2`

Explanation:

Let
`u=1`
`v=x-5`

We know, Quotient Rule

`[vd/dxu-ud/dxv]/v^2`

`[(x-5)d/dx1-1d/dx(x-5)]/(x-5)^2`

`[(x-5)*0-1*1]/(x-5)^2=(-1)/(x-5)^2`

This will be the answer of the differentiated function.