How do you find the derivative of #f(x)=e^(sqrtx)#? Calculus Differentiating Exponential Functions Differentiating Exponential Functions with Base e 1 Answer Andrea S. Feb 15, 2018 #d/dx (e^sqrtx) = e^sqrtx/(2sqrtx)# Explanation: Using the chain rule: #d/dx f(y(x)) = (df)/dy xx dy/dx# with #y=sqrtx#: #d/dx (e^sqrtx) = (d/dy e^y) (d/dx sqrt x)# #d/dx (e^sqrtx) = e^y/(2sqrtx)# #d/dx (e^sqrtx) = e^sqrtx/(2sqrtx)# Answer link Related questions What is the derivative of #y=3x^2e^(5x)# ? What is the derivative of #y=e^(3-2x)# ? What is the derivative of #f(theta)=e^(sin2theta)# ? What is the derivative of #f(x)=(e^(1/x))/x^2# ? What is the derivative of #f(x)=e^(pix)*cos(6x)# ? What is the derivative of #f(x)=x^4*e^sqrt(x)# ? What is the derivative of #f(x)=e^(-6x)+e# ? How do you find the derivative of #y=e^x#? How do you find the derivative of #y=e^(1/x)#? How do you find the derivative of #y=e^(2x)#? See all questions in Differentiating Exponential Functions with Base e Impact of this question 1916 views around the world You can reuse this answer Creative Commons License