# How do you find the derivative of f(x)= sin^5 (2x)?

$\mathrm{df} \frac{x}{\mathrm{dx}} = 5 \cdot {\sin}^{4} \left(2 x\right) \cdot \cos 2 x \cdot 2 = 10 \cdot {\sin}^{4} 2 x \cdot \cos 2 x = 5 \cdot {\sin}^{3} \left(2 x\right) \cdot \sin \left(4 x\right)$