Question

How do you find the derivative of `f(x)=x^2-3x-3x^-2`?

Answer 1

The derivative is a linear operator, so you can differentiate term by term using the general formula:

`(d(x^n))/dx =n x^(n-1)`

Explanation:

`(df)/dx =d(x^2-3x-3x^(-2))/dx=d(x^2)/dx-3d(x)/dx-3d(x^-2)/dx =`

`= 2x -3 +6x^(-3)`