Question

How do you find the derivative of `f(y)=3y^-1+4y`?

Answer 1

`d/(dy) (3y^(-1)+4y) =-3y^(-2)+4`

Explanation:

Using the general rule:

`d/(dy) (y^n) = ny^(n-1)`

And as the differentiation is linear, so:

`d/(dy) (af(y)+bg(y))= a (d/(dy) f(y) )+ b(d/(dy) g(y))`

we have:

`d/(dy) (3y^(-1)+4y) =-3y^(-2)+4`