# How do you find the derivative of g(t) = 1/sqrt(t)?

g'(t)=(-1)/(2t^(3/2)
differentiate using the $\textcolor{b l u e}{\text{power rule}}$
$g \left(t\right) = \frac{1}{\sqrt{t}} = \frac{1}{t} ^ \left(\frac{1}{2}\right) = {t}^{- \frac{1}{2}}$
rArrg'(t)=-1/2t^(-3/2)=(-1)/(2t^(3/2))=(-1)/(2sqrt(t^3)