# How do you find the derivative of  sin(2x + 2)?

$\frac{d}{\mathrm{dx}} \sin \left(u\right) = u ' \cos \left(u\right)$
$\frac{d}{\mathrm{dx}} \sin \left(2 x + 2\right) = \frac{d}{\mathrm{dx}} \left(2 x + 2\right) \cdot \cos \left(2 x + 2\right)$
$\frac{d}{\mathrm{dx}} \sin \left(2 x + 2\right) = \textcolor{red}{2 \cos \left(2 x + 2\right)}$