How do you find the derivative of $sqrt(x-3)$ ?

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Answer 1 · 2016-08-07T20:52:04

$y^'=1/(2sqrt(x-3))$

$y=sqrt (u)" ; "y^'=u^'/(2sqrt(u))$

$y=sqrt(x-2)$

$u=x-3" ; "u^'=1$

$y^'=1/(2sqrt(x-3))$

How do you find the derivative of sqrt(x-3)sqrt(x-3)?