How do you find the derivative of sqrt(x-3)?

Aug 7, 2016

${y}^{'} = \frac{1}{2 \sqrt{x - 3}}$

Explanation:

$y = \sqrt{u} \text{ ; } {y}^{'} = {u}^{'} / \left(2 \sqrt{u}\right)$

$y = \sqrt{x - 2}$

$u = x - 3 \text{ ; } {u}^{'} = 1$

${y}^{'} = \frac{1}{2 \sqrt{x - 3}}$