# How do you find the derivative of  (x^2-3x+5)/x?

$1 - \frac{5}{x} ^ 2$
$\frac{d}{\mathrm{dx}} \left(\frac{{x}^{2} - 3 x + 5}{x}\right) = \frac{d}{\mathrm{dx}} \left(x - 3 + \frac{5}{x}\right)$
$= 1 - 0 - \frac{5}{x} ^ 2$