How do you find the derivative of # x^2 + xy + y^2 =7#?

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Answer 1 · 2016-10-12T13:15:40

#d/dx(x^2 + xy + y^2) = d/dx(7)#

#d/dx(x^2) + d/dx(xy) + d/dx(y^2) = d/dx(7)#

#2x + y + x(dy/dx) + 2y(dy/dx) = 0#

#x(dy/dx) + 2y(dy/dx) = -y - 2x#

#dy/dx(x + 2y) = -y - 2x#

#dy/dx = (-y - 2x)/(x + 2y)#

#dy/dx = (-(y + 2x))/(x + 2y)#

#dy/dx = -(y + 2x)/(x + 2y)#

Hopefully this helps!