How do you find the derivative of #y=5+sinx#? Calculus Basic Differentiation Rules Power Rule 1 Answer Steve M · Andrea S. Nov 28, 2016 #dy/dx=cosx# Explanation: #d/dx("constant") = 0 # #d/dx(sinx) = cosx # And so if #y=5+sinx => dy/dx=0+cosx=cosx# Answer link Related questions How do you find the derivative of a polynomial? How do you find the derivative of #y =1/sqrt(x)#? How do you find the derivative of #y =4/sqrt(x)#? How do you find the derivative of #y =sqrt(2x)#? How do you find the derivative of #y =sqrt(3x)#? How do you find the derivative of #y =sqrt(x)#? How do you find the derivative of #y =sqrt(x)# using the definition of derivative? How do you find the derivative of #y =sqrt(3x+1)#? How do you find the derivative of #y =sqrt(9-x)#? How do you find the derivative of #y =sqrt(x-1)#? See all questions in Power Rule Impact of this question 3536 views around the world You can reuse this answer Creative Commons License