How do you find the derivative of #y=e^x*sinx#? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions with Base e 1 Answer Andrea S. Jan 3, 2017 #d/(dx) (e^xsinx) =e^x(sinx+cosx)# Explanation: Using the product rule: #d/(dx) (e^xsinx) = e^x * d/(dx)sinx + d/dx(e^x)*sinx = e^x cosx + e^xsinx = e^x(sinx+cosx)# Answer link Related questions What is the derivative of #f(x)=ln(g(x))# ? What is the derivative of #f(x)=ln(x^2+x)# ? What is the derivative of #f(x)=ln(e^x+3)# ? What is the derivative of #f(x)=x*ln(x)# ? What is the derivative of #f(x)=e^(4x)*ln(1-x)# ? What is the derivative of #f(x)=ln(x)/x# ? What is the derivative of #f(x)=ln(cos(x))# ? What is the derivative of #f(x)=ln(tan(x))# ? What is the derivative of #f(x)=sqrt(1+ln(x)# ? What is the derivative of #f(x)=(ln(x))^2# ? See all questions in Differentiating Logarithmic Functions with Base e Impact of this question 29571 views around the world You can reuse this answer Creative Commons License