# How do you find the derivative of y=e^x/x?

if $y = f \frac{x}{g} \left(x\right) \to y ' = \frac{f ' \left(x\right) g \left(x\right) - f \left(x\right) g ' \left(x\right)}{g \left(x\right)} ^ 2$
$y ' = \frac{x {e}^{x} - 1 {e}^{x}}{x} ^ 2 =$
$= {e}^{x} \frac{x - 1}{x} ^ 2$