# How do you find the derivative of #y=sin2x+cos2x+ln(ex)#?

##### 1 Answer

Mar 6, 2015

Your expression is

The last term can be written as

Differentiating throughout with respect to x,

You can now apply the chain rule of differentiation to the first two terms on the right hand side of the equation, to get this

The last term is a constant, so its derivative is 0.