How do you find the derivative of #y = sqrt(5-3x) #?

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Answer 1 · 2016-12-18T08:26:04

Using the Chain Rule, think of your function #y# as:

#y=f(g(x))#

Where:

#g(x)=5-3x#

#f(x)=sqrt(g(x))#

Chain rule allows us to take the derivative considering we perform it in the correct order. (Outside to inside)

So:

#y'=1/2(5-3x)^(-1/2)*(-3)#

#y'=-3/(2sqrt(5-3x))#