How do you find the derivative of #y = (x^2 + sqrtx + 1 ) / x^(3/2)#?
1 Answer
Dec 16, 2017
Explanation:
Start by simplifying:
#y = x^(2 - 3/2) + x^(1/2- 3/2) + x^(0 - 3/2)#
#y = x^(1/2) + x^(-2/2) + x^(-3/2)#
#y = x^(1/2) + x^(-1) + x^(-3/2)#
#y' = 1/2x^(-1/2) - x^(-2) -3/2x^(-5/2)#
#y' = 1/(2x^(1/2)) - 1/x^2 - 3/(2x^(5/2))#
Hopefully this helps!
